Problems, Problems

Saturday 5 May 2007 at 2:22 pm | In Articles | 3 Comments

The Art of Problem Solving (AopS) site encourages, teaches and promotes mathematics competitions from small local ones right up to the International Mathematical Olympiad (IMO). As it says on its front page:

Is math class too easy for you? Looking for a greater challenge?
You’ve come to the right place.

It has an excellent introduction to \LaTeX site and a forum to discuss problems. The forum has an RSS feed where students pose new problems every day. So if you’re “looking for a greater challenge” subscribe to this feed. Here is a random sample of some of the problems posed recently, which range from very easy to extremely difficult. Click on the problem number to go to the discussion on it.

    1. We define addition in a different way to usual; an addition statement is true only if the letters in the addends is a rearrangement of the letters in the sum. For example,
    10 + 6 = 16?
    TEN + SIX = TENSIX = SIXTEN, but to be 16 it would need another E.
    Find a “true” addition a + b = c + d.

    2. Prove that 1+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\dots<2.8.

    3. Let a,b,c be nonzero real numbers. Find all ordered pairs (a,b,c) such that \displaystyle\frac{2(a-b-c)}{a^{2}}=\frac{4b-a-2c}{b^{2}}=\frac{4c-a-2b}{c^{2}}.

    4. f is a continuous complex-valued function satisfying:
    i) |f(z)| = |z|
    ii) |f(z)-z| = |z|
    Find f(f(f(2007)))

    5. If a and b are relatively coprime, find all possible values of \gcd(a+b,a^{2}+b^{2}).

    6. Let A,B,C be three angles of  \triangle ABC. Prove that (1-\cos A)(1-\cos B)(1-\cos C)\ge\cos A\cos B\cos C.

    7. For each function f which is defined for all real numbers and satisfies f(xy)=xf(y)+yf(x) and f(x+y)=f(x^{1993})+f(y^{1993}) determine the value of f(\sqrt{5753}).

    8. Let a,b,c be positive reals such that a+b+c=1. Prove that 7(ab+bc+ca) \le 9abc+2.

    9. For 0 \leq d \leq 9, we define the numbers S_{d}=1+d+d^{2}+\cdots+d^{2006}. Find the last digit of the number S_{0}+S_{1}+\cdots+S_{9}.

    10. The product of several distinct positive integers is divisible by 2006^2. Determine the minimum value the sum of such numbers can take.


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  1. Another similar site is Unfortunately it is in Polish only.

    Comment by jan — Monday 23 June 2008 9:20 am #

  2. art of problem solving is fantastic. It contains so many challenging math problems. Another good thing is that it is linked to, which have even more hard problems.

    Comment by Dave S — Friday 27 June 2008 11:31 am #

  3. They are the same sites, just different skins.

    Comment by steve — Friday 27 June 2008 12:15 pm #

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